14x^2-64=0

Solution for 14x^2-64=0 equation:

14x^2-64=0

a = 14; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·14·(-64)
Δ = 3584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3584}=\sqrt{256*14}=\sqrt{256}*\sqrt{14}=16\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{14}}{2*14}=\frac{0-16\sqrt{14}}{28}
=-\frac{16\sqrt{14}}{28}
=-\frac{4\sqrt{14}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{14}}{2*14}=\frac{0+16\sqrt{14}}{28}
=\frac{16\sqrt{14}}{28}
=\frac{4\sqrt{14}}{7}
$